这道题可以通过异或的方式来写，根据异或^=的性质a^a=0;a^0=a,(a^b=c,c^b=a)下面是代码

#include <bits/stdc++.h>
using namespace std;

int main() {
    string s = "ZWPXBXSWQCZZLX";
    string s1, single, doub;
    char diff1 = 0, diff2 = 0;
    int k;
    cin >> k;
    for (int i = 0; i < s.size(); i++) {
        if (i % 2 == 0) {
            doub += s[i];
            diff1 ^= s[i];
        }
        else {
            single += s[i];
            diff2 ^= s[i];
        }
    }
    for (int j = 0; j < k; j++) {
        cin >> s1;
        char diff11 = diff1, diff22 = diff2;
        for (int i = 0; i < s1.size(); i++) {
            if (i % 2 == 0) {
                diff11 ^= s1[i];
            }
            else {
                diff22 ^= s1[i];
            }
        }
        if (diff11 == 0 && diff22 == 0) {
            cout << "YES" << endl;
        }
        else {
            cout << "NO" << endl;
        }
    }
    return 0;
}